Answer with Explanation:
We are given that
Inner radius of outer conductor=[tex]r_2[/tex]
Outer radius of outer conductor=[tex]r_3[/tex]
Radius of inner conductor=[tex]r_1[/tex]
Current=I
a.Consider a loop of radius r<r1 Then, the current in the loop
[tex]I'=\frac{I}{\pi r^2_1}\times \pi r^2=\frac{Ir^2}{r^2_1}[/tex]
Magnetic field withing the inner conductor,B=[tex]\frac{\mu_0I'}{2\pi r}[/tex]
[tex]B=\frac{\mu_0\times Ir^2}{2\pi r\times r^2_1}=\frac{\mu_0Ir}{2\pi r^2_1}[/tex]
b.Consider the loop of radius r where [tex]r_1<r<r_2[/tex]
Then, I'=I
[tex]B=\frac{\mu_0I}{2\pi r}[/tex]
c.Consider a loop of radius r
There is no current therefore,
B=0
